14x^2-50+24=0

Solution for 14x^2-50+24=0 equation:

14x^2-50+24=0

We add all the numbers together, and all the variables

14x^2-26=0

a = 14; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·14·(-26)
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{91}}{2*14}=\frac{0-4\sqrt{91}}{28}
=-\frac{4\sqrt{91}}{28}
=-\frac{\sqrt{91}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{91}}{2*14}=\frac{0+4\sqrt{91}}{28}
=\frac{4\sqrt{91}}{28}
=\frac{\sqrt{91}}{7}
$